Preparation for the exam in chemistry tests. Online Gia Chemistry Tests. Appointment of KIM USE

The state final certification of 2019 in chemistry for graduates of the 9th grade of general educational institutions is carried out in order to assess the level of general education of graduates in this discipline. The tasks test knowledge of the following sections of chemistry:

The structure of the atom.
Periodic law and Periodic system of chemical elements D.I. Mendeleev.
The structure of molecules. Chemical bond: covalent (polar and non-polar), ionic, metallic.
Valency of chemical elements. The degree of oxidation of chemical elements.
Simple and complex substances.
Chemical reaction. Conditions and signs of chemical reactions. Chemical equations.
Electrolytes and non-electrolytes. Cations and anions. Electrolytic dissociation of acids, alkalis and salts (medium).
Ion exchange reactions and conditions for their implementation.
Chemical properties of simple substances: metals and non-metals.
Chemical properties of oxides: basic, amphoteric, acidic.
Chemical properties of bases. Chemical properties of acids.
Chemical properties of salts (medium).
Pure substances and mixtures. Rules for safe work in the school laboratory. Chemical pollution of the environment and its consequences.
The degree of oxidation of chemical elements. Oxidizing agent and reducing agent. Redox reactions.
Calculation of the mass fraction of a chemical element in a substance.
Periodic law D.I. Mendeleev.
Initial information about organic substances. Biologically important substances: proteins, fats, carbohydrates.
Determination of the nature of the medium of a solution of acids and alkalis using indicators. Qualitative reactions to ions in solution (chloride, sulfate, carbonation, ammonium ion). Qualitative reactions to gaseous substances (oxygen, hydrogen, carbon dioxide, ammonia).
Chemical properties of simple substances. Chemical properties of complex substances.

Date of passing the OGE in chemistry 2019:
June 4 (Tuesday).

There are no changes in the structure and content of the examination paper in 2019 compared to 2018.

In this section you will find online tests that will help you prepare for passing the OGE (GIA) in chemistry. We wish you success!

The standard OGE test (GIA-9) of the 2019 format in chemistry consists of two parts. The first part contains 19 tasks with a short answer, the second part contains 3 tasks with a detailed answer. In this regard, only the first part (i.e., the first 19 tasks) is presented in this test. According to the current structure of the exam, among these tasks, only 15 answers are offered. However, for the convenience of passing the tests, the site administration decided to offer answers in all tasks. But for tasks in which answer options are not provided by the compilers of real control and measuring materials (KIMs), the number of answer options has been significantly increased in order to bring our test as close as possible to what you will have to face at the end of the school year.

The standard OGE test (GIA-9) of the 2018 format in chemistry consists of two parts. The first part contains 19 tasks with a short answer, the second part contains 3 tasks with a detailed answer. In this regard, only the first part (i.e., the first 19 tasks) is presented in this test. According to the current structure of the exam, among these tasks, only 15 answers are offered. However, for the convenience of passing the tests, the site administration decided to offer answers in all tasks. But for tasks in which answer options are not provided by the compilers of real control and measuring materials (KIMs), the number of answer options has been significantly increased in order to bring our test as close as possible to what you will have to face at the end of the school year.

The standard OGE test (GIA-9) of the 2017 format in chemistry consists of two parts. The first part contains 19 tasks with a short answer, the second part contains 3 tasks with a detailed answer. In this regard, only the first part (i.e., the first 19 tasks) is presented in this test. According to the current structure of the exam, among these tasks, only 15 answers are offered. However, for the convenience of passing the tests, the site administration decided to offer answers in all tasks. But for tasks in which answer options are not provided by the compilers of real control and measuring materials (KIMs), the number of answer options has been significantly increased in order to bring our test as close as possible to what you will have to face at the end of the school year.

The standard OGE test (GIA-9) of the 2016 format in chemistry consists of two parts. The first part contains 19 tasks with a short answer, the second part contains 3 tasks with a detailed answer. In this regard, only the first part (i.e., the first 19 tasks) is presented in this test. According to the current structure of the exam, among these tasks, only 15 answers are offered. However, for the convenience of passing the tests, the site administration decided to offer answers in all tasks. But for tasks in which answer options are not provided by the compilers of real control and measuring materials (KIMs), the number of answer options has been significantly increased in order to bring our test as close as possible to what you will have to face at the end of the school year.

The standard OGE test (GIA-9) of the 2015 format in chemistry consists of two parts. The first part contains 19 tasks with a short answer, the second part contains 3 tasks with a detailed answer. In this regard, only the first part (i.e., the first 19 tasks) is presented in this test. According to the current structure of the exam, among these tasks, only 15 answers are offered. However, for the convenience of passing the tests, the site administration decided to offer answers in all tasks. But for tasks in which answer options are not provided by the compilers of real control and measuring materials (KIMs), the number of answer options has been significantly increased in order to bring our test as close as possible to what you will have to face at the end of the school year.

When completing tasks A1-A19, select only one correct option.
When completing tasks B1-B3, select two correct options.

When completing tasks A1-A15, select only one correct option.

When completing tasks A1-A15, choose only one correct option.

For 2-3 months it is impossible to learn (repeat, pull up) such a complex discipline as chemistry.

There are no changes in KIM USE 2020 in chemistry.

Don't delay your preparation.

Before starting the analysis of tasks, first study theory. The theory on the site is presented for each task in the form of recommendations that you need to know when completing the task. guides in the study of the main topics and determines what knowledge and skills will be required when completing the USE tasks in chemistry. For the successful passing of the exam in chemistry, theory is the most important thing.
Theory needs to be backed up practice constantly solving problems. Since most of the errors are due to the fact that I read the exercise incorrectly, I did not understand what is required in the task. The more often you solve thematic tests, the faster you will understand the structure of the exam. Training tasks developed on the basis of demos from FIPI give them the opportunity to decide and find out the answers. But do not rush to peek. First, decide for yourself and see how many points you have scored.

Points for each task in chemistry

1 point - for 1-6, 11-15, 19-21, 26-28 tasks.
2 points - 7-10, 16-18, 22-25, 30, 31.
3 points - 35.
4 points - 32, 34.
5 points - 33.

Total: 60 points.

The structure of the examination paper consists of two blocks:

Questions that require a short answer (in the form of a number or word) - tasks 1-29.
Tasks with detailed answers - tasks 30-35.

3.5 hours (210 minutes) are allotted to complete the examination paper in chemistry.

There will be three cheat sheets on the exam. And they need to be dealt with.

This is 70% of the information that will help you successfully pass the exam in chemistry. The remaining 30% is the ability to use the provided cheat sheets.

If you want to get more than 90 points, you need to spend a lot of time on chemistry.
To successfully pass the exam in chemistry, you need to solve a lot: training tasks, even if they seem easy and of the same type.
Correctly distribute your strength and do not forget about the rest.

Dare, try and you will succeed!

Specification
control measuring materials
for holding the unified state exam in 2016
in chemistry

1. Appointment of KIM USE

The Unified State Examination (hereinafter referred to as the USE) is a form of objective assessment of the quality of training of persons who have mastered the educational programs of secondary general education, using tasks in a standardized form (control measuring materials).

The USE is conducted in accordance with Federal Law No. 273-FZ of December 29, 2012 “On Education in the Russian Federation”.

Control measuring materials allow to establish the level of development by graduates of the Federal component of the state standard of secondary (complete) general education in chemistry, basic and profile levels.

The results of the unified state examination in chemistry are recognized by educational institutions of secondary vocational education and educational institutions of higher professional education as the results of entrance examinations in chemistry.

2. Documents defining the content of KIM USE

3. Approaches to the selection of content, the development of the structure of the KIM USE

The basis of approaches to the development of KIM USE 2016 in chemistry was those general methodological guidelines that were determined during the formation of examination models of previous years. The essence of these settings is as follows.

KIM are focused on testing the assimilation of the knowledge system, which is considered as an invariant core of the content of existing programs in chemistry for general education organizations. In the standard, this system of knowledge is presented in the form of requirements for the preparation of graduates. These requirements correspond to the level of presentation in the KIM of the content elements being checked.
In order to ensure the possibility of a differentiated assessment of the educational achievements of graduates of the KIM USE, they check the development of basic educational programs in chemistry at three levels of complexity: basic, advanced and high. The educational material on the basis of which tasks are built is selected on the basis of its significance for the general educational preparation of secondary school graduates.
The fulfillment of the tasks of the examination work involves the implementation of a certain set of actions. Among them, the most indicative are, for example, such as: to identify the classification features of substances and reactions; determine the degree of oxidation of chemical elements according to the formulas of their compounds; explain the essence of a particular process, the relationship of the composition, structure and properties of substances. The ability of the examinee to carry out various actions when performing work is considered as an indicator of the assimilation of the studied material with the necessary depth of understanding.
The equivalence of all variants of the examination work is ensured by maintaining the same ratio of the number of tasks that test the assimilation of the main elements of the content of the key sections of the chemistry course.

4. The structure of KIM USE

Each version of the examination work is built according to a single plan: the work consists of two parts, including 40 tasks. Part 1 contains 35 tasks with a short answer, including 26 tasks of a basic level of complexity (the serial numbers of these tasks: 1, 2, 3, 4, ... 26) and 9 tasks of an increased level of complexity (the serial numbers of these tasks: 27, 28, 29, ...35).

Part 2 contains 5 tasks of a high level of complexity, with a detailed answer (the serial numbers of these tasks: 36, 37, 38, 39, 40).

To solve problems of this type, it is necessary to know the general formulas for classes of organic substances and the general formulas for calculating the molar mass of substances of these classes:

Majority Decision Algorithm tasks to find the molecular formula includes the following steps:

- writing reaction equations in general form;

- finding the amount of substance n, for which the mass or volume is given, or the mass or volume of which can be calculated according to the condition of the problem;

- finding the molar mass of the substance M = m / n, the formula of which must be established;

- finding the number of carbon atoms in a molecule and compiling the molecular formula of a substance.

Examples of solving problem 35 of the Unified State Examination in chemistry to find the molecular formula of organic matter by combustion products with an explanation

The combustion of 11.6 g of organic matter produces 13.44 liters of carbon dioxide and 10.8 g of water. The vapor density of this substance in air is 2. It has been established that this substance interacts with an ammonia solution of silver oxide, is catalytically reduced by hydrogen to form a primary alcohol, and is capable of being oxidized by an acidified solution of potassium permanganate to a carboxylic acid. Based on these data:
1) establish the simplest formula of the starting substance,
2) make its structural formula,
3) give the reaction equation for its interaction with hydrogen.

Decision: the general formula of organic matter is CxHyOz.

Let's translate the volume of carbon dioxide and the mass of water into moles using the formulas:

n = m/M and n = V/ Vm,

Molar volume Vm = 22.4 l/mol

n (CO 2) \u003d 13.44 / 22.4 \u003d 0.6 mol, => the original substance contained n (C) \u003d 0.6 mol,

n (H 2 O) \u003d 10.8 / 18 \u003d 0.6 mol, => the original substance contained twice as much n (H) \u003d 1.2 mol,

This means that the desired compound contains oxygen in the amount:

n(O)= 3.2/16 = 0.2 mol

Let's look at the ratio of C, H and O atoms that make up the original organic matter:

n(C) : n(H) : n(O) = x: y: z = 0.6: 1.2: 0.2 = 3: 6: 1

We found the simplest formula: C 3 H 6 O

To find out the true formula, we find the molar mass of an organic compound using the formula:

M (CxHyOz) = Dair (CxHyOz) * M (air)

M ist (CxHyOz) \u003d 29 * 2 \u003d 58 g / mol

Let's check if the true molar mass corresponds to the molar mass of the simplest formula:

M (C 3 H 6 O) \u003d 12 * 3 + 6 + 16 \u003d 58 g / mol - corresponds, \u003d\u003e the true formula coincides with the simplest.

Molecular formula: C 3 H 6 O

From the data of the problem: "this substance interacts with an ammonia solution of silver oxide, is catalytically reduced by hydrogen to form a primary alcohol, and is capable of being oxidized by an acidified solution of potassium permanganate to a carboxylic acid" we conclude that it is an aldehyde.

2) In the interaction of 18.5 g of saturated monobasic carboxylic acid with an excess of sodium bicarbonate solution, 5.6 l (n.o.) of gas were released. Determine the molecular formula of the acid.

3) Some limiting carboxylic monobasic acid with a mass of 6 g requires the same mass of alcohol for complete esterification. This yields 10.2 g of ester. Set the molecular formula of the acid.

4) Determine the molecular formula of acetylenic hydrocarbon if the molar mass of the product of its reaction with an excess of hydrogen bromide is 4 times greater than the molar mass of the original hydrocarbon

5) During the combustion of organic matter with a mass of 3.9 g, carbon monoxide (IV) with a mass of 13.2 g and water with a mass of 2.7 g were formed. Derive the formula of the substance, knowing that the hydrogen vapor density of this substance is 39.

6) During the combustion of organic matter weighing 15 g, carbon monoxide (IV) with a volume of 16.8 l and water with a mass of 18 g were formed. Derive the formula of the substance, knowing that the vapor density of this substance in terms of hydrogen fluoride is 3.

7) During the combustion of 0.45 g of gaseous organic matter, 0.448 l (n.o.) of carbon dioxide, 0.63 g of water and 0.112 l (n.o.) of nitrogen were released. The density of the initial gaseous substance in nitrogen is 1.607. Find the molecular formula of this substance.

8) The combustion of oxygen-free organic matter produced 4.48 l (N.O.) of carbon dioxide, 3.6 g of water and 3.65 g of hydrogen chloride. Determine the molecular formula of the burned compound.

9) During the combustion of organic matter weighing 9.2 g, carbon monoxide (IV) was formed with a volume of 6.72 l (n.o.) and water with a mass of 7.2 g. Set the molecular formula of the substance.

10) During the combustion of organic matter weighing 3 g, carbon monoxide (IV) was formed with a volume of 2.24 l (n.o.) and water with a mass of 1.8 g. It is known that this substance reacts with zinc.
Based on these conditions of the assignment:
1) make the calculations necessary to establish the molecular formula of an organic substance;
2) write down the molecular formula of the original organic matter;
3) make a structural formula of this substance, which unambiguously reflects the order of bonding of atoms in its molecule;
4) write the equation for the reaction of this substance with zinc.

However, it is often chosen by students who wish to enter universities of the corresponding direction. This test is necessary for those who want to further study chemistry, chemical engineering and medicine, or will specialize in biotechnology. It is inconvenient that the date of the exam coincides with the exam in history and literature.

However, these subjects are rarely taken together - they are too different in focus for universities to require the results of the USE in such a set. This exam is quite difficult - the percentage of those who fail it ranges from 6 to 11%, and the average test score is about 57. All this does not contribute to the popularity of this subject - chemistry is only seventh in the ranking of popularity among graduates of past years.

The exam in chemistry is important for future doctors, chemists and biotechnologists

Demo version of the USE-2016

USE dates in chemistry

early period

April 2, 2016 (Sat) - Main exam
April 21, 2016 (Thu) - Reserve

main stage

June 20, 2016 (Mon) - Main exam
June 22, 2016 (Wed) - Reserve

Changes in the USE-2016

Unlike last year, some general innovations appeared in the examination in this discipline. In particular, the number of tests that will have to be solved at the basic level has been reduced (from 28 to 26), and the maximum number of primary points in chemistry is now 64. As for the specific features of the 2016 exam, some of the tasks have undergone changes in the answer format, which should give the student.

In task No. 6, you need to demonstrate whether you know the classification of inorganic compounds and choose 3 answers out of 6 options offered in the test;
Tests numbered 11 and 18 are designed to determine whether the student knows the genetic links between organic and inorganic compounds. The correct answer involves choosing 2 options from the 5 specified formulations;
Tests No. 24, 25 and 26 require an answer in the form of a number that must be determined independently, while a year ago, schoolchildren had the opportunity to choose an answer from the proposed options;
In numbers 34 and 35, students should not only choose answers, but establish a correspondence. These tasks are related to the topic "Chemical properties of hydrocarbons".

In 2016, the chemistry exam includes 40 tasks

General information

The exam in chemistry will last 210 minutes (3.5 hours). The examination ticket includes 40 tasks, which are divided into three categories:

A1–A26- relate to tasks that allow assessing the basic training of graduates. The correct answer to these tests makes it possible to score 1 primary point. You should spend 1-4 minutes to complete each task;
B1–B9- these are tests with an increased level of complexity, they will require schoolchildren to briefly formulate the correct answer and in total they will make it possible to score 18 primary points. Each task is given 5-7 minutes;
С1–С5- belong to the category of tasks of increased complexity. In this case, the student is required to formulate a detailed answer. In total, you can get another 20 primary points for them. Each task can be given up to 10 minutes.

The minimum score in this subject must be at least 14 primary points (36 test points).

How to prepare for the exam?

To pass the statewide chemistry exam, you can download and work through the demo versions of the exam back in advance. The proposed materials give an idea of what you will have to face at the exam in 2016. Systematic work with tests will allow you to analyze gaps in knowledge. Practicing on the demo version allows students to quickly navigate through the real exam - you do not waste time trying to calm down, focus and understand the wording of the questions.